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3 years ago

Help please! will mark brainliest! lots of points

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

Answer:

The new width is 20

Step-by-step explanation:

w = 45

h = 27

We want the height to be 12

We can use proportions to find the new dimensions

w w old w new

----- = ---------- = ----------

h h old h new

45 w new

---------- = ----------

27 12

Using cross products

45*12 = 27 * w new

540 = 27 w new

Divide by 27

540/27 = 27 w new/27

20 = w new

The new width is 20

mariarad [96]3 years ago

3 0

Answer:

7 1/5 cm

Step-by-step explanation:

45/27 = 12/x

x = 12*27 / 45

x = 324/45

x = 7 9/45

= 7 1/5

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Can you guys help me to find the measure of each angle tysm.

barxatty [35]

Answer:

∠EBF = 51°

∠DBE = 17°

∠ABF = 141°

∠EBA = 90°

∠DBC = 107°

∠DBF = 68°

Step-by-step explanation:

Hope this helps

7 0

3 years ago

Read 2 more answers

A. identify the parent function of the given graph.

Paha777 [63]

The parent function is f(x) = x^3

The domain are all x values (-infinity, infinity)

The range are all y values (-infinity, infinity)

4 0

4 years ago

Read 2 more answers

R - 9S = 2 3R - 3S = -10

GrogVix [38]

R-9s=2 add 9s to both sides

r=2+9s making 3r-3s=-10 become:

3(2+9s)-3s=-10 perform indicated multiplication on left side

6+27s-3s=-10 combine like terms on left side

6+24s=-10 subtract 6 from both sides

24s=-16 divide both sides by 24

s=-16/24

s=-2/3, making r-9s=2 become:

r-9(-2/3)=2 perform indicated multiplication on left side

r+6=2 subtract 6 from both sides

r=-4

So s= -2/3 and r= -4

8 0

3 years ago

M 1 = (2x + 28)<br> m 3= (6x + 4)<br> What is m<2<br> Enter your answer in the box.

s2008m [1.1K]

Answer:

m∠2 = 140°

Step-by-step explanation:

m∠1 = m∠3, since they're vertical angles.

Solve for x:

$2x+28=6x+4\\24=4x\\6=x$

Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.

m∠1 = (2(6) + 28)°

m∠1 = (12 + 28)°

m∠1 = 40°

Now that we know m∠1, we can now solve for m∠2.

m∠1 + m∠2 = 180°

40° + m∠2 = 180°

m∠2 = 140°

3 0

3 years ago

A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed

PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

3 0

4 years ago