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vampirchik [111]
3 years ago
14

+2\sqrt{2} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

1 + \sqrt{2}

Step-by-step explanation:

\sqrt{(1+\sqrt{2} } )^{2}

1 + \sqrt{2}

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Part 1) Intervals of the domain where the  graph is above the x-axis (f(x) > 0)

Part 2) location on graph where input is zero  (y-intercept)

Part 3) location on graph where output is zero  (x-intercept)

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<u><em>Verify each case</em></u>

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Intervals of the domain where the  graph is above the x-axis

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location on graph where input is zero  

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y-intercept

Part 3) we have

location on graph where output is zero  

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x ---> the independent variable or input value

f(x) ---> the dependent variable or output value

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The x-intercept is the value of x (input value) when the value of the function f(x) (output value) is zero

therefore

x-intercept

Part 4) we have

Intervals of the domain where the  graph is below the x-axis

we know that

If the graph is below the x-axis, then the value of f(x) is negative

therefore

f(x) < 0

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