4 years ago

Find the common factor and rewrite. Type your answer in the box. Do not use any spaces.

Mathematics

1 answer:

den301095 [7]4 years ago

5 0

Answer:

1(8a+11a)

Step-by-step explanation:

The greatest common factor is 1 and 8a/1=8a and 11a/1=11.

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If k is the midpoint of LM and k (-4,-6) and m(-7,-3). find l (endpoint)

Fudgin [204]

Answer:

(-1,-9) PLEASE MARK BRAINLIEST!!!!!

Step-by-step explanation:

k(-4,-6) , m(-7,-3)

-7+4=-3

-3+6=3

-4+3=-1

-6-3=-9

(-1,-9)

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3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

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3 years ago

What is the answer to -8x-9>-21

dybincka [34]

<h3>:- Solution</h3>

-8x - 9 > -21

Move -9 to right side

-8x > -21 + 9

-8x > -12

x < -12/-8

x < 3/2

the answer to -8x - 9 > -21 is x < 3/2

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3 years ago

If 2 cards are drawn from a deck of cards, what is the probability that they are bot spades?

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