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marin [14]
3 years ago
10

A bag contains 5 red marbles, 10 blue marbles, and 14 yellow marbles. If Jen selects a marble from the bag without looking, what

is the probability that she will not pull a red marble
Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

The answer to your question is  0.83 or 83%

Step-by-step explanation:

Data

5 red marbles

10 blue marbles

14 yellow marbles

Process

1.- Calculate the total amount of marbles

    Total amount = 5 red + 10 blue + 14 yellow

     Total amount = 29 marbles

2.- Calculate the amount of marbles that are not red

     No red marbles = 10 + 14

                                = 24 marbles

3.- Calculate the probability

Probability of not pulling a red marble = \frac{no red marble}{total amount of marbles}

Probability of not pulling a red marble = \frac{24}{29} = 0.83 or 83%

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5

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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

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(\sqrt{n})^{2} = (18.5658)^{2}

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4 0
3 years ago
A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
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Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

a+s=243

and the student tickets sold were 2x the adult tickets, we can do

s=2a

We can replace s in the first equation adding to 243 with 2a

a+s(2a)=243\\3a=243\\

Step 2:

Solve for a. We can divide both sides by 3.

a=81

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

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