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dezoksy [38]
3 years ago
13

What is the measure of the largest angle on the triangle!

Mathematics
2 answers:
nalin [4]3 years ago
6 0
Okay, so as you may know the inside angles of a triangle always add up to 180! so you must first find x, so that means add up all equations to find x. your answer is 41




























jeka57 [31]3 years ago
5 0
The answer would be A
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How many zeroes are in the product of 40 x 107?
N76 [4]

Answer:

There's one 0.

Step-by-step explanation:

Because I multiplied it and there's only one 0.

4 0
3 years ago
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Hello there
Dafna1 [17]

Answer:

20

Step-by-step explanation:

2/3 want to go

If there are 30 people, we can find our answer pretty easily as 30 is 10 times more than 3.

2/3 = 20/30

So 20 people would like to go :O

Hope this helps, have a nice day :))

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3 years ago
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A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin
Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

T_1cos\theta_1-T_2cos\theta_2=0           (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

T_1sin\theta_1+T_2sin\theta_2-W=0               (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2

Then, you sum the equations:

T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2        (3)

Next, you use the following identity:

sin^2\theta+cos^2\theta=1

and you obtain in the equation (3):

T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°

With this values you can calculate the value of the another angle, by using the equation (1):

\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0
3 years ago
Please help!!!!!!!!!!!!!!!
tamaranim1 [39]

Answer:

(y¹-y¹/x¹-x¹)

8-11/10-19

-3/-9

1/3

Step-by-step explanation:

1/3 or one-third is your answer!

7 0
2 years ago
Plz help ..............!!!!!
lana [24]

Answer:

1.8

is the median

4 0
3 years ago
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