Answer:220
Step-by-step explanation:
LET X BE THE LENGTH OF RECTANGLE AND FOR UPPER PORTION OF DIA GRAM BASE OF RIGHT ANGLE TRIANGLE SO X=20
LET Y BE WIDTH OF RECTANGLE SO Y=8
LET P BE THE PERPENDICULAR OF THE RIGHT TRIANGLE SO P=6
THEN
AREA OF RECTANGLE=LENGTH*WIDTH
SO AREA OF RECTANGLE BECOMES=(20)(8)=160
AND AREA OF RIGHT ANGLE TRIANGLE BECOMES=1/2(BASE*(PERPENDICULAR)
SO =1/2(20)(6)=60
SO THE TOTAL AREA OF THE DIAGRAM=AREA OF RIGHT ANGLE TRIANGLE+AREA OF RECTANGLE=160+60=220
Answer:
The water is 208.22ft from the tug boat
Step-by-step explanation:
The governing equation is 
y is the height above the ocean
x is the distance from the tugboat
if y= 6ft, the equation will now become

we can arrange this properly to form a quadratic equation by grouping like terms.

solving quadratically we have two values of x as 208.22ft and 0.873 ft.
We can take a more realistic value as a solution to our problems:
208.22ft