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2 years ago

1-cos^2 A / sec^2 A - tan^2 A

1 answer:

6 0

I hope this helps you

✔cos^2A+sin^2A=1

✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA

secA=1/cosA

tgA=sinA/cosA

sin^2A/1/cos^2A-sin^2A/cos^2A

sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A

sin2A.2.sin2A/cos2A

tg2A.2.sin2A

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The 759 students in Chad's middle school.44% participate in sports, 29% play in the band,

stellarik [79]

Answer:

A - 220

B - 205

Step-by-step explanation:

29% of 759 is 220.11, round down so it stays 220.

27% of 759 is 204.93 round up so it becomes 205.

bonus:

44% of 759 is 333.96 round up and it becomes 334.

to check your work, add 220, 205, and 334 and its 759. thats how you can be sure its correct.

hope this helps :)

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2 years ago

The diagram shows a right angled triangle use pythagoras theorem to work out length of side ac

Strike441 [17]

Answer:

Step-by-step explanation:

Using Pythagoras theorem,

AC^2 = AB^2 + BC^2

AC^2 = 4^2 + 15^2

AC^2 = 16 + 225

AC^2 = 241

AC = √241

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3 years ago

Find AE<br> Note: Figure is not to scale<br><br> (Graded)

murzikaleks [220]

Answer: i think its 82 but im not sure

Step-by-step explanation:

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3 years ago

A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

3 0

3 years ago

Find the area of the shaded figure in the diagram below. Use 3.14 for π and round your answer to the nearest hundredth.

kirill [66]

Answer:

Step-by-step explanation:

diameter of 1 circle = 21.3/3= 7.1

radius of 1 circle= 7.1/3=3.55

area of 1 circle =πr^2=3.14× (3.55)^2=39.57

area of 3 circle= 39.57×3=118.72

therefore,area of shaded portion= area of 3 circle =118.72

7 0

2 years ago