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aleksandrvk [35]
2 years ago
12

Can u pls help me with this question ​

Mathematics
1 answer:
Triss [41]2 years ago
7 0

Step-by-step explanation:

what's the question or put pictures???

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N-m-m; use m=6,and n=-5
mixas84 [53]
(-5)-(6)-(6)
-5+-6
-11+-6
-17
-17 is the answer you are looking for.
8 0
2 years ago
Simplify 4(5+t)+2t<br> Please explain steps taken
Digiron [165]

Answer:

6t+20

Step-by-step explanation:

4(5+t)+2t =

= 20+4t+2t =

= 20+6t =

= 6t+20

6 0
3 years ago
What is the measure of the missing angle?<br><br> 76<br> 166<br> 86<br> 156
BabaBlast [244]

Answer:

156

Step-by-step explanation:

It the whole line’s angle measure would be 180 degrees. If you subtract 24 from 180 You get 156.

Please give me Brainly answer.

5 0
3 years ago
Read 2 more answers
Can you also find out the same thing for 3/4 I would highly appreciate it so I won't have to break this up!
s2008m [1.1K]
28/50: decimal: .56
percent: 56%
I think...
5 0
3 years ago
Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky
cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of stars in a given volume of space.

X\sim \text{Poisson}\ (\lambda=1)

The probability mass function of <em>X</em> is:

p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

P(X=2)=\frac{e^{-1}\times 1^{2}}{2!}=\frac{e^{-1}}{2}=\frac{0.36788}{2}=0.18394\approx 0.184

(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

P(X\geq 3)=1-P(X

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in <em>t</em> cubic light years there will be, [<em>t</em> × (1/16)] stars.

7 0
3 years ago
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