(x2-y1)²+(2xy)1 =
x⁴-2x²y²+y⁴+4x²y² =
x⁴+2x²y²+y⁴=
(x²+y²)²
Answer:
do not know
Step-by-step explanation:
<u><em>Answer:</em></u>

<u><em>Explanation:</em></u>
We know that the initial value of a function is the output of the function when the input is zero.
In other words, it is the value of f(x) when x = 0
<u>Now, checking the given table, we can find that:</u>
at x = 0 ...............> f(x) = 
<u>This means that</u> the output is
when the input is zero which means that our initial value is 
Hope this helps :)
The answer is 1.609 i hope this helps
good luck