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OLEGan [10]
2 years ago
12

Write the equation of a line that has a m= -5 and passes through the point (-1,4)

Mathematics
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer:

We have a slope and a point, this way, we do not need to find the slope using two points. We can find the line using the Slope Form to turn it into Slope-Intercept Form, also known as "y = mx + b". We can use the Slope Form which is "y - y1 = m(x - x1)". A coordinate is "(x,y)", so that means, "(-1,4)" means that x = -1 and y = 4. We can substitute y1 for 4 and x1 for -1, and m for -5 since m is the slope. Plugging that information into the Slope Form Formula we get "y - 4 = -5(x - (-1))". We know that a negative with a negative turn positive, so we can use this information to change the formula to "y - 4 = -5(x + 1)". Now we distribute and simplify, these steps are shown below.

y - 4 = -5(x + 1)

y - 4 = -5x -5

y - 4 + 4 = -5x - 5 + 4

y = -5x - 1

Now that we have simplified it, we can see that the slope is -5 and the -1 is the y-intercept. To check this is a linear equation is to graph it, or substitute three x-coordinate or y-coordinates and draw a line. In conclusion, the equations is y = -5x - 1.

Step-by-step explanation:

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3 years ago
Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3
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Answer:

Step-by-step explanation:

We have the polynomial

16n^3+13n^2+7n-10   ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

8n^3 +11n^2 - 5n  - 5\\ 8n^3+2n^2 + 12n - 5\\

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16n^3+13n^2+7n-10

that is what we was looking for

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