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3 years ago

William had $45 dollars to spend on vegetables. After buying 6

Mathematics

2 answers:

Leno4ka [110]3 years ago

7 0

They each costed around $3.25 each!

olasank [31]3 years ago

5 0

Let the cost of one watermelon be 'x'.

Amount of money spent by William on vegetables = $45

Number of watermelons bought by William = 6

Amount left with William = $25.50

Equation will be,

45 - 6x = 25.50

Add -45 on both sides,

45- 45 - 6x = 25.50 -45

-6x = - 19.50

Divide both side by -6 to find the value of x

$\frac{-6x}{-6}$ = $\frac{-19.50}{-6}$

x= $\frac{-19.50}{-6}$

x = 3.25

So the cost of each watermelon is $3.25

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Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

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$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

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We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

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Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

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$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

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