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3 years ago

14

Christine ate 1/3 of her pie. Jimmy ate 1/2 of his pie. How much of a pie did they eat in all?

2 answers:

docker41 [41]3 years ago

7 0

2 4 6
3 6
1/3 x 2 = 2/6 1/2 x 3 = 3/6, so they ate 5/6 in all

vitfil [10]3 years ago

7 0

.38 or 19/50 is how much pie they ate in all

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A recent study was conducted in which a random sample of men and a random sample of women were surveyed about whether they were

Feliz [49]

Answer:

e. We are 99% confident that the difference in the population percents of all men and women who are fans of a professional football team is between 13.3% and 20.7%.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

99% confidence interval for the difference in the proportion of fans of a professional football team between men and women is of (0.133, 0.207)

The interpretation is that we are 99% sure that the true proportion is in this interval for the entire population, so the correct answer is given by option e.

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3 years ago

B a C Which of these angles are adjacent angles?

BigorU [14]

Answer: a and c

Step-by-step explanation:

I know it’s not b but isn’t adjacent angel two angels?

Correct me if I’m wrong

3 0

3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Henry counted 350 lockers in his school. Hayley counted 403 lockers in her school. How does the 3 in 350 compare to the 3 in 403

viva [34]

The 3 in 350 is in the hundred place and in 403 the 3 is in the ones place

3 0

2 years ago

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What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?

lianna [129]

Answer:

x = 200

Step-by-step explanation:

1/5x – 2/3y = 30

substitute in y

1/5x - 2/3(15) = 30

multiply

1/5x - 10 = 30

isolate the variable

1/5x = 40

multiply each side by 5

x = 200

4 0

3 years ago

Read 2 more answers