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kvv77 [185]
3 years ago
14

Christine ate 1/3 of her pie. Jimmy ate 1/2 of his pie. How much of a pie did they eat in all?

Mathematics
2 answers:
docker41 [41]3 years ago
7 0
2 4 6
 3 6 
  1/3 x 2 =  2/6     1/2 x 3 = 3/6, so they ate 5/6 in all                                                                                                     
vitfil [10]3 years ago
7 0
.38 or 19/50 is how much pie they ate in all
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A recent study was conducted in which a random sample of men and a random sample of women were surveyed about whether they were
Feliz [49]

Answer:

e. We are 99% confident that the difference in the population percents of all men and women who are fans of a professional football team is between 13.3% and 20.7%.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

99% confidence interval for the difference  in the proportion of fans of a professional football team between men and women is of (0.133, 0.207)

The interpretation is that we are 99% sure that the true proportion is in this interval for the entire population, so the correct answer is given by option e.

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3 years ago
B a C Which of these angles are adjacent angles?​
BigorU [14]

Answer: a and c

Step-by-step explanation:

I know it’s not b but isn’t adjacent angel two angels?

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3 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

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Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
Henry counted 350 lockers in his school. Hayley counted 403 lockers in her school. How does the 3 in 350 compare to the 3 in 403
viva [34]
The 3 in 350 is in the hundred place and in 403 the 3 is in the ones place
3 0
2 years ago
Read 2 more answers
What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
lianna [129]

Answer:

x = 200

Step-by-step explanation:

1/5x – 2/3y = 30

substitute in y

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multiply

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isolate the variable

1/5x = 40

multiply each side by 5

x = 200

4 0
3 years ago
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