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3 years ago

What is the answer I need to know

Mathematics

1 answer:

kolezko [41]3 years ago

3 0

K = -18 to check, -4 + k/3 = -10 is the equation. -18/3 = -6, and -4 + -6 = -10. Mark as branliest if you can. :)

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Which fractions are equivalent to 15/20

Digiron [165]

Answer:

$\frac{3}{4}$ , $\frac{30}{40}$ , $\frac{45}{60}$ , $\frac{60}{80}$ ....e.t.c are all equivalent fractions

Step-by-step explanation:

For the answer you need to know bout equivalent fractions

TO find equivalent fractions you have to multiply the numerator and denominator by the same amount

E.x. $\frac{15}{20}=\frac{(15)(2)}{(20)(2)} =\frac{30}{40}$

Therefore $\frac{30}{40}$ is an equivalent fraction

8 0

2 years ago

The graph of an exponential function is shown on the grid.

aliya0001 [1]

Answer:

????

Step-by-step explanation:

Where is the picture?

P.S. I am not answering this question JUST to get points, I will actually revise my answer correctly once you add in a picture! :)

3 0

3 years ago

If ABCD is a kite.<br> find m

Dvinal [7]

The answer would be 115°, the sum of interior angles in a kite is always 360° so if 41° and 89° equal 130° subtract 130° from 360° and that gives you 230° divide that by two for each side of the kite missing and you get 115°

5 0

2 years ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

1 year ago

Question 19 of 25

asambeis [7]

It is going to b (4.12)

4 0

2 years ago