Answer:
I believe the answer is D :)
Answer:
Step-by-step explanation:
According to the table, function g(x) reaches the max height of 33, approx.
The equation of motion is f(x) = -16x^2 + 42x + 12. We need to determine the maximum of this function. To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.
Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.
So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6
I am not sure about this. I am sure that 3 has atleast 1.
You did south, north, correctly
but last one
twice north is 2 times (x+48) or 2x+96
so
s=x
n=x+48
c=4x
s+c>2x+96
subsitute s for x and 4x for c
x+4x>2x+96
5x>2x+96
minus 2x both sides
3x>96
divide both sides by 3
x>32
it cannot be equal to 32 so
the minimum value is 33 spaces in south car park
