Answer:
The program to this question as follows:
Program:
def lettersOnly(s): #defining method lettersOnly
val="" #defining string variable that return value
for i in s: #defining loop to calculate value
if(i.isalpha()): #check condition that value is string
val=val+ i #add value
return val #return value
print(lettersOnly("data3base_ro1c3k5s")) #call method and print value
Output:
databaserocks
Explanation:
In the above python code, a method lettersOnly is declared that accepts a string variable "s" in its parameter. Inside the method, a string variable "val", and loop is declared, in which the "val" variable holds method return value.
- In the loop and if block is used that uses "isalpha" string method, which checks the check alphabetic character in the given value. if this is true it will calculate all value in "val" variable and return its value.
- At the last, the print method is used, which calls the lettersOnly method and prints its return value.
D)When the query is run again, the data that meets the new criteria will be retrieved.
Answer:
d
Explanation:
All of the above can be means by which signals or information is transferred.
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
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