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Paul [167]
3 years ago
9

What is computer?explain any five characteristic in short.​

Computers and Technology
2 answers:
Serjik [45]3 years ago
5 0

Answer:

A programmable electronic device designed to accept data, perform prescribed mathematical and logical operations at high speed and display the results of these operations. Mainframes, desktop and laptop computers, tablets, and smartphones are some of the different types of computers.

Characteristics of Computer System:

= Speed. A computer works with much higher speed and accuracy compared to humans while performing mathematical calculations. ...

= Accuracy. Computers perform calculations with 100% accuracy. ...

= Diligence. A computer can perform millions of tasks or calculations with the same consistency and accuracy. ...

= Versatility. ...

=Reliability. ...

= Memory.

miv72 [106K]3 years ago
4 0

Answer:

computer is an electronic machine which work on the basic principle" ipo"(input process and output.

it's characteristics are

Accuracy

Computers perform calculations with 100% accuracy. Errors may occur due to data inconsistency or inaccuracy.

Diligence

A computer can perform millions of tasks or calculations with the same consistency and accuracy. It doesn’t feel any fatigue or lack of concentration. Its memory also makes it superior to that of human beings.

Versatility

Versatility refers to the capability of a computer to perform different kinds of works with same accuracy and efficiency.

Reliability

A computer is reliable as it gives consistent result for similar set of data i.e., if we give same set of input any number of times, we will get the same result.

You might be interested in
Write a C program that counts the number of vowels in a word. The C program reads words from an input file and then stores in an
polet [3.4K]

Answer:

Explanation:

The following code is written in C and does what the question requires. It uses the input file reads it and outputs the number of vowels to the file called output.dat

#include <ctype.h>

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

int str_count_in_chars(char *start, char *end, char *chars) {

   int count = 0;

   for (; start != end; count += !!strchr(chars, *(start++)));

   return count;

}

void str_swap_in_chars(size_t str_len, char **str, char *chars) {

   for (int front = 0, back = str_len - 1; front < back; front++) {

       if (strchr(chars, (*str)[front])) {

           for (; !strchr(chars, (*str)[back]); back--);

           char tmp = (*str)[front];

           (*str)[front] = (*str)[back];

           (*str)[back--] = tmp;

       }

   }

}

char *file_to_str(FILE *fin) {

   int buf_len = 64;

   char buf[buf_len];

   char *str = malloc(buf_len);

   str[0] = '\0';

   for (int i = 1; fgets(buf, buf_len, fin); i++) {

       if (!(str = realloc(str, i * buf_len))) {

           fprintf(stderr, "%s:%d realloc failed\n", __FILE__, __LINE__);

           exit(1);

       }

       strcat(str, buf);

   }

   return str;

}

int main() {

   char *vowels = "aeiou";

   FILE *fin = fopen("input.dat", "r");

   FILE *fout = fopen("output.dat", "w");

   if (!fin || !fout) {

       fprintf(stderr, "%s:%d fopen failed\n", __FILE__, __LINE__);

       exit(1);

   }

   char *words = file_to_str(fin);

   fclose(fin);

   int words_len = strlen(words);

   for (int i = 0; i < words_len;) {

       if (isspace(words[i])) {

           fputc(words[i++], fout);

           continue;

       }

       int start = i;

       for (; i < words_len && !isspace(words[i]); i++);

       char *word = words + start;

       int word_len = i - start;

       int vowel_count = str_count_in_chars(word, words + i, vowels);

       if (vowel_count % 2 == 0) {

           str_swap_in_chars(word_len, &word, vowels);

       }

       fprintf(fout, "%.*s_%dvow", word_len, word, vowel_count);

   }

   fclose(fout);  

   free(words);

   return 0;

}

5 0
3 years ago
A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca
natima [27]

Answer:

There are 5,598,527,220 ways to choose <em>5</em> cards of type 1, <em>4 </em>cards<em> </em>of type 2, <em>2</em> cards of type 3 and <em>2</em> cards of type 4 from a set of 13 cards.

Explanation:

The <em>crucial point</em> of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of <em>combination</em> since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for <em>combinations</em> is \\ \frac{n!}{(n-k)!k!}, where <em>n</em> is the total of elements available and <em>k </em>is the size of a selection of <em>k</em> elements  from which we can choose from the total <em>n</em>.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287, since \\ \frac{8!}{8!} = 1.

Choosing 4 cards of type 2 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715, since \\ \frac{9!}{9!} = 1.

Choosing 2 cards of type 3 from a 13-card deck:

\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78, since \\ \frac{11!}{11!}=1.

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78.

We still need to make use of the <em>Multiplication Principle</em> to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the <em>multiplication</em> of all them.

5 0
4 years ago
Which of the following internet connection types is known to have a significantly higher latency than the others
Degger [83]
What are the options?
7 0
4 years ago
When parallel parking, you should select a space that is __________ as long as your car.
Shtirlitz [24]

that is Equally as long as your car


7 0
4 years ago
______ have become a common and easily created form of malware that are creating using applications such as Visual Basic or VBSc
Helen [10]

Answer:

Macro Viruses

Explanation:

Macro Viruses have become a common and easily created form of malware that are creating using applications such as Visual Basic or VBScript.

7 0
3 years ago
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