What kind of operating system is MS-DOS?

When building systems, the only two entities that constitute software engineering are people and process.

VLD [36.1K]

Answer: False

Explanation: Software engineering is the designing, analyzing, creating the software application as per the requirement of the user. The programming languages is the base for the designing of the application the software engineering field.

At the time of building system ,there is the requirement of many resources for the development.There is the requirement of the software skills, programming knowledge, resources and tools for the working and designing.Thus, there are different resources, people,skills processes, problem solving skill etc required for the building of the system.

7 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

1 year ago

CPT (Current Procedural Terminology) codes consist of 3-4 numbers representing a unique service. True False

xz_007 [3.2K]

This is in fact false to my knowledge

4 0

3 years ago

You need to design a data storage scheme for Hayseed Heaven library data system. There are several hundred thousand large data r

Alekssandra [29.7K]

Answer:

Make use of hash tables

Explanation:

The appropriate thing to use for this should be a hash table.

A Hash Table can be described as a data structure which stores data in an associative manner. In a hash table, data is stored in an array format, where each data value has its own unique index value. Access of data becomes very fast if we know the index of the desired data. So we can perform Hashing on ISBN Number since its unique and based on the Hash Function w ecan store the Information record.

There is no requirement for printing the file in order - HashTables dont store the data in order of insertions, so no problems with that

It becomes a data structure in which insertion and search operations are very fast irrespective of the size of the data. So Querying books details can be fast and searching will take less time.

It can also be pointed out that it wont be too expensive for Hardware implemtation as HashTables stores data based on Hash Functions and memory consumption is also optimal which reduces memory wastages.

7 0

3 years ago

Between which zones and a DMZ should firewalls be placed? Choose two answers.

brilliants [131]

Answer:

Internal and External Zones

Explanation:

Demilitarized Zone (DMZ) in a network means that, we make sure the security of network at higher level as military make sure the security of their bases or zones.

In this type of network, The network of the internal organization (LAN) needs security from hackers and unauthorized users who are trying to access the resources and information from the network.

This network is divided into two major zones. A DMZ has been placed between two zones along with firewalls enhance the security of LAN Network from the networks on internet. These two zones are named as Internal and External Zone. The firewall between DMZ and External zones monitors the users from external networks on the internet who tries to access organization's network. Internal network monitors the traffic between DMZ and Internal LAN network.

4 0

3 years ago