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3 years ago

What is the difference between the fractions? Use the number line to help find the answer.

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

3 0

Answer:

The difference is $\frac{3}{10}$

Step-by-step explanation:

We must find the common denominator of the fractions.

The common denominator of $\frac{1}{2}$ and $\frac{1}{5}$ is $2*5=10$ ; therefore we have

$\frac{1}{2}=\frac{5}{10}$

$\frac{1}{5} =\frac{2}{10}$

now it is easy to subtract $\frac{5}{10} -\frac{2}{10}$ using the number line: we have to move $\frac{3}{10}$ units to the left in order to get to $\frac{2}{10}$ .

Thus our answer is

$\boxed{\frac{1}{2} -\frac{1}{5}=\frac{3}{10} }$

o-na [289]3 years ago

3 0

Answer:

-7/10 i believe

Step-by-step explanation:

merry quarentine

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$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 24/5 inches}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 21/5 inches}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

<h3>Given :</h3>

Dimensions of rectangle are $\sf\dfrac{24}{5}$ inches and $\sf\dfrac{21}{5}$ .

$\\ \\$

$\\ \\$

Area of rectangle

$\\ \\$

$\\ \\$

$\bigstar \boxed{ \sf Area \: of \: rectangle = length \times breadth}$

$\\ \\$

$\dashrightarrow \sf{}Area \: of \: rectangle = \dfrac{24}{5} \times \dfrac{21}{5}$

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