Ask question

Ask question

All categories

4 years ago

14

A person is working at a constant rate. If he produces 15 details in 8 hours, how long does he need to work to produce 18 detail

s? Let t be the time he needs to produce 18 details. Please write equation!

1 answer:

Kryger [21]4 years ago

8 0

15=8
15÷3=5
Answer is 20

You might be interested in

The libary has at least 5,000 books witch inequality represent the number of books,b,at the library

Mazyrski [523]

B $\geq$ 5,000

because the library has more than or = to 5000 books.

7 0

4 years ago

He cost, in millions of dollars, of building a three-story high school in new york state was estimated to be c(x) = 2.1 + 0.12x

ratelena [41]

Given cost function is

c(x) = $2.1 + 0.12x - 0.0001x^2$ (20 ≤ x ≤ 400)

where x is the number of thousands of square feet

total revenue will be $0.2 million dollars per thousand square feet

Revenue is 0.2 millions per thousand square feet. we know x is the number of thousand of square feet

So R(x) = 0.2x

We know Profit = Revenue - Cost

P(x) = R(x) - C(x)

$P(x) = 0.2x - (2.1 + 0.12x - 0.0001x^2)$

$P(x) = 0.2x - 2.1 - 0.12x + 0.0001x^2)$

combine like terms

$P(x) =-2.1 + 0.08x + 0.0001x^2$

Profit function is

$P(x) =0.0001x^2 + 0.08x - 2.1$

5 0

3 years ago

Ethan's mom tried a new bean soup recipe. She used 2 cups of black beans and 5 cups of kidney beans. The family loved it, so she

bezimeni [28]

Answer:

no the amount of Kidney beans is not proportional to the amount of black beans

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

3 years ago

If the speed limit of the highway is 60 mph which car exceed the speed limit assume other cars were traveling at a constant spee

Sedaia [141]

Answer:

The first car

Step-by-step explanation:

183/3 = 61mph

6 0

3 years ago

Read 2 more answers