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lesantik [10]
3 years ago
8

The robots are powered on coffee alone. They use 2 bags of coffee each day. How long will 1/4 of a bag of coffee last them

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0

probably about 1//8th of a day


Vadim26 [7]3 years ago
5 0
2 bags = 24 hours
Therefore 1 bag = 12 hours, half a bag = 6 hours and 1/4 of a bag must be? 3 hours :)
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a jar contains 36 marbles. it has 20 red, 12 black, and 4 green marbles. two marbles are drawn; the first is not returned before
Igoryamba
P(red) first drawn:
20/36=5/9
P(red) second drawn:
19/35

95/315 or 19/63. As a result, the probability that both marbles are red is 19/63. Hope it help!
7 0
3 years ago
What is the solution to 0.25t = 0.25 - t ?
Ede4ka [16]

i think it's t=0.2    Hope it helps:)

8 0
3 years ago
How to solve for a, b,
professor190 [17]

It looks like the length of a and b should be the same. You can use the Pythagorean theorem (only works with right triangles):

a² + b² = c² (c is the hypotenuse or the longest side of the triangle, a and b are the other side lengths of the triangle)

a² + (4)² = (5)²

a² + 16 = 25

a² = 9

a = 3

a and b have a length of 3

3 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
Write an inequality to represent the phrase: The product of a number and 5 is at least 45
lutik1710 [3]
See the photo attached

7 0
3 years ago
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