Answer:
we need to prove : for every integer n>1, the number
is a multiple of 5.
1) check divisibility for n=1,
(divisible)
2) Assume that
is divisible by 5, 
3) Induction,



Now, 



Take out the common factor,
(divisible by 5)
add both the sides by f(k)

We have proved that difference between
and
is divisible by 5.
so, our assumption in step 2 is correct.
Since
is divisible by 5, then
must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number
is a multiple of 5.
I think it would be 8-3, not 7. 8x - 2x + 5x = (8-5)x + 5x
M=-2/5 is the answer to this equation
Answer:a^2+2ab+b^2
Step-by-step explanation:
First write it out in extended form, (a+b)(a+b) then multiply each term by the other in each parenthesis, such as a*a+b*b+a*b+a*b
Then, once you have done that, simplify it. you will then get the answer a^2+2ab+b^2