A scientist wants a 66 ounce saline solution with concentration 12% . She has concentrations of 4% and 15% . How much of each so
lution must she use to get the desired concentration?
1 answer:
Let x and y represent the measure in ounces of the two given saline solutions. We are mixing these two together, so x + y = 66 ounces.
The amount of the 4% solution to be used is 0.04x, and that of the 15% solution is 0.15y.
This results in the equation .04x + 0.15y = 66(0.12).
Multiply both sides by 100 to remove the decimal fractions. Then
4x + 15y = 66(12). Now eliminate the variable x by recalling that x + y = 66 ounces, so that x = 66 - y.
Substituting, 4(66 - y) + 15y = 66(12)
Expanding, 264 - 4y + 15 y = 792
combining like terms: 11y = 528
Solving for y: y = 528/11 = 48. Then x = 66 - 48 = 18.
Use 48 ounces of the 15% solution and 18 ounces of the 4% solution to obtain 66 ounces of a 12% solution.
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