Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
The expression 256 + 4 is equivalent to (200 + 4) + (40+4) + (16+4) according to distributive and commutative property of addition.
Given the expression 256 + 4. This can be solved using the partial sum expressed as:
256 + 4
256 + 4
= (200 + 40 + 16) + 4
According to the commutative property, A+B = B+A
The arrangement does not affect the result. Hence;
- (200 + 40 + 16) + 4 = 4 + (200 + 40 + 16)
Using the distributive law;
- 4 +(200 + 40 + 16) = (200 + 4) + (40 + 4) + (16 + 4)
Hence the expression 256 + 4 is equivalent to (200 + 4) + (40+4) + (16+4) according to distributive and commutative property of addition.
Learn more on partial sum here: brainly.com/question/6958503
The -4 will translate the graph of f(x) 4 units to the right.
Then the -2 before the x will stretch it vertically with factor 2, then reflect it in the y -axis.
Finally the + 5 will translate the graph 5 units vertically upwards
Step-by-step explanation:
In×5z+In×7
=1.67z +1.95-8
=1.67z-6.05
Answer:
The probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Step-by-step explanation:
Given : Cherry trees in a certain orchard have heights that are normally distributed with 
inches and 
inches.
To find : What is the probability that a randomly chosen tree is greater than 140 inches?
Solution :
Mean - inches
Standard deviation - inches
The z-score formula is given by, 
Now,
The Z-score value we get is from the Z-table,
Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.
