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3 years ago

6

I need help asap! due tomorrow and am clueless!!

1 answer:

Lady bird [3.3K]3 years ago

6 0

2 b 3 c 4 e 5a 6 b 7 d it's the awnsers 2 thru 7

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Will mark brainliest answer, please answer !!

Elina [12.6K]

I think it is 9 - x because 81-x^2/9-x = 9-x

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2 years ago

Read 2 more answers

Which number should follow in this series: 64/64 9/12 6/12

zheka24 [161]

Answer: $\frac{1}{4}$

Step-by-step explanation:

You can reduce the fractions, then:

$\frac{64}{64}=1$

$\frac{9}{12}=\frac{3}{4}$

$\frac{6}{12}=\frac{3}{6}=\frac{1}{2}$

Rewrite them as following:

$1,\frac{3}{4},\frac{1}{2}$

If you subtract the first number and the second number, you obtain:

$1-\frac{3}{4}=\frac{1}{4}$

If you subtract the second number and the second number, you obtain:

$\frac{3}{4}-\frac{1}{2}=\frac{1}{4}$

Therefore, you must subtract $\frac{1}{2}$ and $\frac{1}{4}$ to obtain the number asked. Then, this is:

$\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

6 0

3 years ago

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Which statment is true

Paraphin [41]

I think hamburger and French fries

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3 years ago

How old would you be today if you were born in 1977?

Montano1993 [528]

Current year is 2016
born year is 1977

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2016 - 1977
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5 0

3 years ago

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Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$

Therefore we can use the formula and

$\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n = \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16 = 15/8$

5 0

2 years ago