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erik [133]
3 years ago
14

A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?​

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0

9514 1404 393

Answer:

  3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

  A = LW = 12a^2

  P = 2(L+W) = 14a

Using the second equation, we can find L:

  L +W = 7a . . . . . divide by 2

  L = 7a -W

Substituting into the area formula gives the quadratic ...

  (7a -W)(W) = 12a^2

  W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

  (W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

  W = 3a, L = 4a

  W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

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3 years ago
Find the values of x and y.
timurjin [86]

Answer:

x= 38

y= 71

Step-by-step explanation:

The triangle shown in the figure is an isosceles triangle, a triangle having two sides equal.

The two sides marked with a "dash" are said to be equal.

<h3 /><h3><u>STEP I:</u></h3>

If we label off the triangle as ABC with AD being the extended length (containing 108°).

We'll get,

AB = AC

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 /><h3><u>STEP II:</u></h3>

*Property*

<em>"</em><em>I</em><em>f</em><em> </em><em>two</em><em> </em><em>sides</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>are</em><em> </em><em>equal</em><em> </em><em>their</em><em> </em><em>corresponding</em><em> </em><em>base</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>equal</em><em> </em><em>too</em><em>.</em><em>"</em>

=> <u>∠BAC = ∠BCA </u> . . . . (¡)

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 /><h3><u>STEP</u><u> </u><u>III</u><u>:</u></h3>

From the figure, ∠BCA is equal to y.

*Property*

<em>"</em><em>Two</em><em> </em><em>angles</em><em> </em><em>on</em><em> </em><em>a</em><em> </em><em>straight</em><em> </em><em>line</em><em> </em><em>sum</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>180</em><em>°</em><em>"</em>

∠BAC can be found out by subtracting 109° from the straight angle (180°).

=> ∠BAC = 180 - 109

=> <u>∠BAC = 71°</u>

Substituting these values in eqn. (¡):

71 = y

Hence, the value of y is 71°

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3 /><h3><u>STEP</u><u> </u><u>IV</u><u>:</u></h3>

*Property*

<em>"</em><em>The</em><em> </em><em>exterior</em><em> </em><em>angle</em><em>(</em><em>angle</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>extended</em><em> </em><em>side</em><em>)</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>it's</em><em> </em><em>interior</em><em> </em><em>opposite</em><em> </em><em>angles</em><em>.</em><em>"</em>

Here,

  • Interior angles = x and y (= 71)
  • Exterior Angle = 109°

=> 109 = x + 71

=> 109 - 71 = x

=> x = 38°

Hence, the value of x is 38°.

4 0
2 years ago
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