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liraira [26]
3 years ago
10

How do i solve inequalities and graph it’s solution

Mathematics
1 answer:
EleoNora [17]3 years ago
6 0
What is the inequality equation??
And you can easily put in your graphing calculator and press graph...
but I think equation might help batter.
I hope you get it...
I am sorry if you don’t
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100 POINTS!!!!!!!!!!!<br><br><br><br>The bottom one is &lt; 1 and &lt; 3
luda_lava [24]

Answer:

B. <1 and <5

Step-by-step explanation:

they look exactly the same

6 0
3 years ago
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What is the y-intercept of y=-3x + 6?<br> O 6<br> -3<br> 3<br> 0 6
Bezzdna [24]

Answer:

6

Step-by-step explanation:

Slope intercept form is y=mx+b, with m being the slope and be being the y intercept, so when you look for what b is in the equation for y=-3x+6 then 6 is b.

5 0
2 years ago
Two restaurants each surveyed diners to find out the ages of people eating at their restaurants. The box plots show the results
ipn [44]

Answer:

Restaurant A served a greater variety of ages than Restaurant B, because the range of date for Restaurant A is greater than that of Restaurant B.

Step-by-step explanation:

3 0
2 years ago
The length of a rectangle is 4 centimeters is longer than its width. What are the possible integral widths if the area of the re
velikii [3]

Answer: 23

Step-step by explanation:

w(w+4)=437

w^2+4w-437=0

(w+23)(w-19)=0

w=19,-23

w<19

l<23!!

5 0
3 years ago
3. Two balls are drawn in succession without replacement from an urn containing 4 red balls and 3 blue balls. Find the probabili
choli [55]

Answer:

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

Step-by-step explanation:

Given that :

Number of red balls = 4

Number of Blue balls = 3

Total number of balls = (4 + 3) = 7

Picking without replacement :

Number of picks = 2

1st pick is red :

Probability = (required outcome / Total possible outcomes)

USing combination formula :

nCr = n! / (n-r)! r!

Total possible outcome :

7C2 = 7! / 5!2! = 7*6 / 2 = 42 / 2 = 21

X = number of red

For red = 0;

P(x =0) = required outcome / Total possible outcomes

P(x = 0)

Required outcome : [4C0 * 3C2)]

P(x = 0) = [(4C0 * 3C2)] / 21 = (1*3)/21 = 3/21 = 1/7

P(x = 1)

Required outcome : [4C1 * 3C1)]

P(x = 1) = [(4C1 * 3C1)] / 21 = (4*3)/21 = 12/21 = 4/7

P(x = 2)

Required outcome : [4C2 * 3C0)]

P(x = 2) = [(4C2 * 3C0)] / 21 = (6*1)/21 = 6/21 = 2/7

Hence ;

X ____ 0 ______ 1 _______ 2

P(x) __ 1/7 _____ 4/7 _____ 2/7

8 0
3 years ago
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