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3 years ago

Solve these compound interest problems and round your answer to the nearest 100th.

Mathematics

1 answer:

MatroZZZ [7]3 years ago

4 0

Answer:

$2,226.96

Step-by-step explanation:

You are going to want to use the compound interest formula, which is shown below.

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate

n = number of times compounded annually

t = time

First, change 10% into its decimal form:

10% -> $\frac{10}{100}$ -> 0.1

Now lets plug in the values into the equation:

$A=500(1+\frac{0.1}{12})^{15(12)}$

$A=2,226.96$

The final amount after 15 years is $2,226.96

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Pls help I don’t understand

dmitriy555 [2]

The answer is c. $\frac{46}{9}$

a. $\frac{11}{5}=2.2$ (2.2≠5.11) (2.2 is not equal to 5.11)

b. $5\frac{1}{8}=\frac{5}{8}$ or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. $\frac{46}{9} =5.11$ (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

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3 years ago

HELP PLZ ...........WITH ALL OF THEM

Setler79 [48]

Answer:

1/2

Step-by-step explanation:

We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.

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3 years ago

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Nata [24]

The graph is stretch/shrunk by a factor of a. The Domain is h=

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2 years ago

Show that f(x) = 9x - 2 is a one-to-one function. number

GREYUIT [131]

Answer:

upon graphing, it is linear

Step-by-step explanation:

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3 years ago

The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg

amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

$\\ 0.239 =\frac{239}{1000}\;or\;23.9\%$

Step-by-step explanation:

From the question, we have the following information:

The distribution for protein requirement is normally distributed.
The population mean for protein requirement for adults is $\\ \mu= 0.65 gP*kg^{-1}*d^{-1}$
The population standard deviation is $\\ \sigma =0.07 gP*kg^{-1}*d^{-1}$

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about the proportion of the population that has a requirement less than $\\ x = 0.60 gP*kg^{-1}*d^{-1}$ .

For answering this, we need to calculate a z-score to obtain the probability of the value x in this distribution using a standard normal table available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

$\\ z = \frac{x - \mu}{\sigma}$

For the given parameters, we have:

$\\ z = \frac{0.60 - 0.65}{0.07}$

$\\ z = -0.7142857$

<h3>Determining the probability</h3>

With this value for z at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is symmetrical.

Tables have values for z with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the standard normal table gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

$\\ P(x$

$\\ P(x$ (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

$\\ 0.239 =\frac{239}{1000}\;or\;23.9\%$

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0

3 years ago