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Kazeer [188]
4 years ago
7

What are the factors on which pressure exerted by a liquid depend​

Physics
1 answer:
Dmitry [639]4 years ago
4 0

\huge\mathfrak\red {Answer:}

Pressure within a liquid depends only on the

  • density of the liquid,
  • the acceleration due to gravity,
  • and the depth within the liquid.

The pressure exerted by such a static liquid increases linearly with increasing depth.

\mathfrak\purple {Hope\: this\: helps\: you...}

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Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet
amid [387]

Responder:  

18.75 atmósferas  

Explicación:  

Paso uno:  

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

<em><u>La presión final es de 18.75 atm.</u></em>

5 0
3 years ago
What part of that antonym determines if it will combine or break apart from another substance
emmasim [6.3K]
<h2>Answer</h2>

The <u>electron affinity in chemical reaction</u> decides the formation of breakdown of substance

<h2>Explanation</h2>

Within the chemical reactions, different reactants are come together to make the new compound to complete up to the reaction. The reaction is based on the stability of reactants and the electron affinity of these reactants. The oxidation and reduction process within the reaction is also the main reason to combine or break the substance. For example

H_2 + F_2 -------> 2HF

The hydron has the ability to lose electron and fluorine has the ability to gain an electron. The strong or weak electron affinity of this element makes the new compound HF.

3 0
3 years ago
Poor measurement practices are likely to lead to data that are.....
zhannawk [14.2K]
Inconsistent. You should take three readings at least.
8 0
3 years ago
Read 2 more answers
Two projectile launchers are beside one another on level ground. Both launchers are directed at the same angle with respect to g
kakasveta [241]

Answer:

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

g = Acceleration due to gravity

Range of a projectile is given by

R=\frac {v^{2}\sin 2\theta}{g}

When Initial velocity = v

R_A=\frac{v^{2}\sin 2\theta}{g}

When Initial velocity = 2v

R_B=\frac{(2v)^{2}\sin 2\theta}{g}\\\Rightarrow R_B=\frac{4v^2\sin 2\theta}{g}

Dividing the equtions, we get

\frac{R_A}{R_B}=\frac{\frac{v^{2}\sin 2\theta}{g}}{\frac{4v^2\sin 2\theta}{g}}

Here, the angle at which the projectiles are fired at are equal.

\frac{R_A}{R_B}=\frac{1}{4}\\\Rightarrow R_B=4R_A

Hence, projectile B will travel 4 times as far as projectile A prior to landing

7 0
3 years ago
A car starts from rest and after 10 seconds is traveling at 20 m/s. Assuming that it continues to accelerate at the same rate it
Alenkinab [10]

Assuming that it continues to accelerate at the same rate it will take another 10 seconds to reach 40 m/s.

Answer:

Explanation:

Since the first question states that there is a change in the velocity from rest to 20 m/s in 10 seconds time interval. So the acceleration experienced by the car during this 10 seconds should be determined first as follows:

Acceleration = (final velocity-initial velocity)/Time

Acceleration = (20-0)/10 = 2 m/s².

So this means the car is traveling with an acceleration of 2 m/s².

As it is stated that the car continues to move with same acceleration, then in the second case, the acceleration is fixed as 2 m/s², initial velocity as 20 m/s and final velocity as 40 m/s. So the time taken for the car to reach this velocity with the constant acceleration value will be as follows:

Time = Change in velocity/Acceleration

Time = (40-20)/2 = 20/2=10 s

So again in another 10 seconds by the car to reach 40 m/s from 20 m/s. Similarly the car will take a total of 20 seconds to reach from rest to 40 m/s value for velocity.

5 0
4 years ago
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