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Triss [41]
3 years ago
12

You read in a science magazine that on the Moon, the speed of a shell leaving the barrel of a modern tank is enough to put the s

hell in a circular orbit above the surface of the Moon (there is no atmosphere to slow the shell).What should be the speed for this to happen? Assume that the radius of the Moon is rM = 1.74×10^6m, and the mass of the Moon is mM = 7.35×10^22kg.
Physics
1 answer:
olga_2 [115]3 years ago
3 0

To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.

Centrifugal acceleration is determined by

a_c = \frac{v^2}{r}

Where,

v = Velocity

r = Radius

From the given data of the moon we know that gravity there is equivalent to

a = 1.62m/s

While the radius of the moon is given by

r = 1.74*10^6m

If we rearrange the function to find the speed we will have to

v = \sqrt{ar}

v = \sqrt{1.6(1.74*10^6)}

v = 1.7km/s

The speed for this to happen is 1.7km/s

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rusak2 [61]

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

v \propto \sqrt{4} = 2  

The factor that the wave speed change is 2.

3 0
3 years ago
The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.
andrey2020 [161]
<span>The speed of longitudinal waves, S, in a thin rod = âšYoung modulus / density , where Y is in N/m^2. So, S = âšYoung modulus/ density. Squaring both sides, we have, S^2 = Young Modulus/ density. So, Young Modulus = S^2 * density; where S is the speed of the longitudinal wave. Then Substiting into the eqn we have (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 *10^6 = 26.01 * 2.7 * 10^ (6+3) = 70.227 * 10 ^9</span>
5 0
3 years ago
The mass number is determined by which particles?
BartSMP [9]
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7 0
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Sav [38]

Answer:

Work = 5941 J

Explanation:

As we know that work done is given by the equation

W = F. d

here we know that

F  = (200 N)\hat i - (149 N) \hat j

also we have

d = (23m) \hat i - (9 m)\hat j

now from above formula we have

W = (200 N\hat i - 149 N \hat j).(23 m\hat i - 9m \hat j)

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3 years ago
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3 years ago
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