1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Triss [41]
3 years ago
12

You read in a science magazine that on the Moon, the speed of a shell leaving the barrel of a modern tank is enough to put the s

hell in a circular orbit above the surface of the Moon (there is no atmosphere to slow the shell).What should be the speed for this to happen? Assume that the radius of the Moon is rM = 1.74×10^6m, and the mass of the Moon is mM = 7.35×10^22kg.
Physics
1 answer:
olga_2 [115]3 years ago
3 0

To solve this problem we will use the definition of the kinematic equations of centrifugal motion, using the constants of the gravitational acceleration of the moon and the radius of this star.

Centrifugal acceleration is determined by

a_c = \frac{v^2}{r}

Where,

v = Velocity

r = Radius

From the given data of the moon we know that gravity there is equivalent to

a = 1.62m/s

While the radius of the moon is given by

r = 1.74*10^6m

If we rearrange the function to find the speed we will have to

v = \sqrt{ar}

v = \sqrt{1.6(1.74*10^6)}

v = 1.7km/s

The speed for this to happen is 1.7km/s

You might be interested in
Does aluminum foil refract light? Why?
nikitadnepr [17]

yes it does it because the material cause it to refract and the stronger it is the more it will refract

4 0
3 years ago
Two astronauts, each having a mass of 74.3 kg are connected by a 13.1 m rope of negligible mass. They are isolated in space, orb
murzikaleks [220]

Answer:

  L = 5076.5 kg m² / s

Explanation:

The angular momentum of a particle is given by

         L = r xp

         L = r m v sin θ

the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1

as we have two bodies

       L = 2 r m v

let's find the distance from the center of mass, let's place a reference frame on one of the masses

        x_{cm} = \frac{1}{M} \sum  x_{i} m_{i}i

        x_{cm} = \frac{1}{m+m} ( 0 + l m)

        x_{cm} = \frac{1}{2m}  lm

        x_{cm} = \frac{1}{2}

        x_{cm} = 13.1 / 2 = 6.05 m

let's calculate

          L = 2  6.05  74.3  5.65

          L = 5076.5 kg m² / s

4 0
3 years ago
Read 2 more answers
At an altitude of 5000 m the rocket's acceleration has increased to 6.9 m/s2 . What mass of fuel has it burned?
sergey [27]

1) Initial upward acceleration: 6.0 m/s^2

2) Mass of burned fuel: 0.10\cdot 10^4 kg

Explanation:

1)

There are two forces acting on the rocket at the beginning:

- The force of gravity, of magnitude F_g = mg, in the downward direction, where

m=1.9\cdot 10^4 kg is the rocket's mass

g=9.8 m/s^2 is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

T=3.0\cdot 10^5 N

According to Newton's second law of motion, the net force on the rocket must be equal to the product between its mass and its acceleration, so we can write:

T-mg=ma (1)

where a is the acceleration of the rocket.

Solving for a, we find the initial acceleration:

a=\frac{T-mg}{m}=\frac{3.0\cdot 10^5-(1.9\cdot 10^4)(9.8)}{1.9\cdot 10^4}=6.0 m/s^2

2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

a'=6.9 m/s^2

The reason for this increase is that the mass of the rocket has decreased, because the rocket has burned some fuel.

We can therefore rewrite eq.(1) as

T-m'g=m'a'

where

m' is the new mass of the rocket

Re-arranging the equation and solving for m', we find

m'=\frac{T}{g+a}=\frac{3.0\cdot 10^5}{9.8+6.9}=1.8\cdot 10^4 kg

And since the initial mass of the rocket was

m=1.9 \cdot 10^4 kg

This means that the mass of fuel burned is

\Delta m = m-m'=1.9\cdot 10^4 - 1.80\cdot 10^4 = 0.10\cdot 10^4 kg

3 0
3 years ago
What is the process of conduction in terms of particle movement
ivann1987 [24]
<span>What is the process of conduction in terms of particle movement chocies

</span>
8 0
3 years ago
What are some alike things between the ozone layer and the greenhouse effect
umka2103 [35]
The ozone layer traps heat from the sun's heat. only three-fourths are reflected back out into space by the ozone layer. the greenhouse effect traps carbon dioxide and so does the ozone layer.
6 0
3 years ago
Other questions:
  • A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a
    9·1 answer
  • Suppose that we repeat the experiment, except that we place the sodium flame in a strong, localized electric field. The field ch
    9·1 answer
  • A small airplane has to reach a speed if 27.8 m/s to takeoff. It can accelerate at 2.00 m/s^2. What is the minimal length of run
    15·1 answer
  • What are two similarities of meiosis and mitosis?
    14·1 answer
  • Two vectors, X and Y, form a right angle. Vector X is 48 inches long and vector Y is 14 inches long. the length of the resultant
    10·1 answer
  • A capacitor with plates separated by a distance d is charged to a potential difference ΔVC. All wires and batteries are disconne
    13·1 answer
  • Two stones are launched from the top of a tall building. One stoneis thrown in a direction 30.0^\circ above the horizontal with
    6·1 answer
  • what is the final speed of an object that starts from rest and accelerates uniformly at 4.0 meters per second over a distance of
    14·1 answer
  • Which best describes the motion of the object between 1
    11·1 answer
  • What is the current in a 120V circuit if the resistance is 20Ω?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!