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3 years ago

Poor measurement practices are likely to lead to data that are.....

Physics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Inconsistent. You should take three readings at least.

Lilit [14]3 years ago

4 0

Answer: incosistent

Explanation: Hi, Measurement refers to the quantification of results obtained by using measurement tools.

Poor measurement practices are likely to lead to inaccurate results and inconsistent data.

To prevent inaccuracy is required to have a calibration program for the equipment used to determine a target's size, length, weight, capacity, or other aspect.

Measurement is fundamental to the sciences; to engineering, construction, and other technical fields; and to almost all everyday activities.

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When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.

Readme [11.4K]

F=K*X,
F=M*a

M*a=K*X

2.5*9.81=K*0.0276

24.525=K*0.0276

24.525/0.0276=K

K= 888.6 N/m ---- force constant

assuming 2.5 refers to the new extension, just divide F/ 0.025
to get

981N/m

8 0

4 years ago

3. A very brittle piece of iron metal (C=.44 J/gC) is heated to 200 C and placed

lubasha [3.4K]

Answer:The temperature of a piece of Metal X with a mass m of 95.4g increases from 25.0°C to 48.0°C as the metal absorbs 849 J of heat.

Explanation:

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2 years ago

1. A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your

allochka39001 [22]

F-mg=ma
F-(12kg)(9.8m/s^2)=(12kg)(1.2m/s^2)
F-117.6N=14.4N
F=132 Newtons

5 0

4 years ago

What is the effect of a larger acceleration on launch velocity?

vredina [299]

Answer:

Concept: Physical Concepts

A larger acceleration, which is the change in velocity divided by the change in time is the theta or the angle that it climbs to.
Secondly the launch velocity is higher or faster and traveles a further distance.

7 0

3 years ago

Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

$\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}$

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

$\displaystyle U_i = K_f$

Substitute and solve for final velocity:
$\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\ 2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ & =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}$

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0

2 years ago