Question

What are the vertical and horizontal asymptotes for the function f(x)=3^2/x^-4

Answer 1

The vertical asymptotes x = - 2, 2 and Horizontal asymptotes y = 3

Option A is the correct answer.

What are Function?

Function are mathematical statement which links an independent variable to dependent variable.

It always comes with a defined domain and range.

The equation mentioned is incorrect in the question w.r.t. to the solutions mentioned, The right equation is

$\rm f(x) = \dfrac{3 x^2}{x^{2}-4}$

This function can also be written as

$\rm f(x) = \dfrac{3 x^2}{x^{2}-2^2}\\\\\rm f(x) = \dfrac{3 x^2}{(x+2)(x-2)}$

Vertical asymptotes are defined when the denominator of a rational function tends to zero.

To find the equation/s let the denominator equal zero.

Denominator tends to zero for x = -2 and x = +2

Horizontal Asymptote is when the function f(x) is tending to zero.

for x = +∞ and x = - ∞

Let the rational function $f(x)= \dfrac{mx^a}{nx^b}$  where  and a and b are degree of numerator and denominator.

If a < b , then the y axis y = 0 is a horizontal asymptote.

If b = a then horizontal asymptote is the line y = p/q

Here the value is b = 2 and a = 2

Since b = a the horizontal asymptote is the line

y = m/n  where m = 3 and n = 1

Therefore y = 3

So , vertical asymptotes x = - 2, 2

Horizontal asymptotes y = 3

Option A is the correct answer.

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