R2(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0<span><span>r2</span>(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0</span>
<span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=0</span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=<span>0
Now </span></span></span> divide through by <span><span>r≠0</span><span>r≠0</span></span>
and get
<span><span>rcos<span>2ϕ</span>−2cosϕ=0</span><span>rcos<span>2ϕ</span>−2cosϕ=0</span></span>
or
<span><span>r=2<span><span>cosϕ</span><span>cos<span>2ϕ</span></span></span></span><span>r=2<span><span>cosϕ</span><span>cos<span>2<span>ϕ</span></span></span></span></span></span>
First you should find the area of the rectangle in the middle.
A: 9 x 6 = 54
Then you can find the area of the triangle on the right.
A: 6 x 5 = 30/2 = 15
Then you can do the triangle on the right.
11-9 = 2
A: 2 x 6 = 12/2 = 6
Then you can add it all together.
15 + 6 + 54 = 74
So the area of the irregular shape is 74.
I hope this helps!
You could say 84/2, 126/3, or even 168/4
Answer:
-1.5, -1
Step-by-step explanation:
midpoint formula
(x1 + x2 / 2) , (y1 + y2/ 2)
-6 + 3 / 2 , -8 + 6 / 2
