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Tresset [83]
3 years ago
6

Alexandra has a stand in the marketplace where she sells ground cumin. She has a fixed amount of weekly expenses, and she sells

her cumin for $7.20 per kilogram. If she sells 90 kilograms of cumin, her weekly net profit is $414.
What are Alexandra's weekly expenses?
How much cumin does Alexandra have to sell to cover her weekly expenses?
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

234 are her weekly expenses and she has to sell 32.5 kilos of cumin to just cover her expenses

Step-by-step explanation:

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Use rectangle ABCD and the given information to solve each problem.
solong [7]

Problem 1

<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>

--------------------

Work Shown:

point E = intersection point of diagonals.

x = measure of angle 6

y = measure of angle 8

angle 7 is also x because triangle AED is isosceles (AE = ED)

Focus on triangle AED, the three angles A, E, D add to 180

A+E+D = 180

x+80+x = 180

2x+80 = 180

2x = 180-80

2x = 100

x = 100/2

x = 50

So both angles 6 and 7 are 50 degrees.

Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.

(angle7)+(angle8) = 90

50+y = 90

y = 90-50

y = 40

angle 8 = 40 degrees

=================================================

Problem 2

<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>

--------------------

Work Shown:

Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)

angle 3 and angle 4 form a 90 degree angle

x = measure of angle 3

(angle 3)+(angle 4) = 90

x+29 = 90

x = 90-29

x = 61

Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.

4 0
4 years ago
The following table shows the times of trains between Juno and Odiham.
Luba_88 [7]

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

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Answer:

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Step-by-step explanation:

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Answer:

About 35

Step-by-step explanation:

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