Question

The expression on the left side of an equation is shown below. If the equation has an infinite number of solutions, which expression can be written in the box on the other side of the equation?

Answer 1

Answer:

The correct option is D) -2(x+5)

Step-by-step explanation:

Consider the provided equation.

-5(x+2)+3x=

The above equation is linear equation having one variable.

For an linear equation ax=b

a=0, b=0 in that situation the equation is in the form of 0x=0 for all value of x. Then there are infinitely many solutions.

Now solve the expression on the left side

-5(x+2)+3x

-5x-10+3x

-2x-10

-2(x+5)

Now for 0x=0 form the expression on the right side must be same as the expression on the left side for the provided equation.

Consider the options.

Option A) -5(x-3)+2x

Solve the above expression.

-5x-15+2x

-3x-15

-2(x+5)≠-3x-15

Thus the option is not correct.

Option B) -5x-10

Solve the above expression.

-5x-10

-5(x+2)

-2(x+5)≠-5(x+2)

Thus the option is not correct.

Option C) x-2x+2+3x

Solve the above expression.

x-2x+2+3x

2x+2

2(x+1)

-2(x+5)≠2(x+1)

Thus the option is not correct.

Option D) -2(x+5)

-2(x+5)=-2(x+5)

Hence, the correct option is D) -2(x+5)

Answer 2

The answer is D. -2x+5.

If we simplify the left side of the equation first given, we come to the expression -2x-10.

If we solve for D., we get the same results. Thus, because an equation with all the same variable terms and constants have infinite solutions, the answer is D.

Hope this helps!