Question

Simplify this: log√24+ log6​

Answer 1

simplifying $log\sqrt{24}+log6$ we get $log(12\sqrt{6})$

Step-by-step explanation:

We need to simplify: $log\sqrt{24}+log6$

Solving:

Applying the rule:

log a + log b = log(ab)

$log\sqrt{24}+log6\\=log(6\sqrt{24})\\\sqrt{24} = \sqrt{2*2*2*3} =\sqrt{2^2*6} =\sqrt{2^2} \sqrt{6}=2\sqrt{6}\\ Putting\,\,value:\\=log(6*2\sqrt{6})\\=log(12\sqrt{6})$

So, simplifying $log\sqrt{24}+log6$ we get $log(12\sqrt{6})$

Keywords: Simplifying Logarithms

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