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3 years ago

Write 3 decimals less than 0.85

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Hello!

Three decimals less then 0.85 are:

1) 0.4

2) 0.5

3) 0.6

I hope it helps!

Romashka [77]3 years ago

3 0

If you're asking 3 separate decimals that are less than .85 you could use .1, .2 and .3

But if you are asking .85 - 3 decimals, then it would be 0.82 because .85 - 3 is .82.

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Your Bank account balance was $235 and 24. After two checks were cashed (each for the same amount) your balance is now -45.58. W

elena55 [62]

235.24 + 45.58 = 280.82

280.82/2 = 140.41

each check was for $140.41

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3 years ago

Subtract (-2x² +3x-5) from( 6x2 -4x+2)

Andreyy89

Answer:

8x² - 7x + 7

General Formulas and Concepts:

<u>Pre-Algebra</u>

Distributive Property

<u>Algebra I</u>

Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

(6x² - 4x + 2) - (-2x² + 3x - 5)

<u>Step 2: Simplify</u>

Distribute negative: 6x² - 4x + 2 + 2x² - 3x + 5
Combine like terms (x²): 8x² - 4x + 2 - 3x + 5
Combine like terms (x): 8x² - 7x + 2 + 5
Combine like terms (Z): 8x² - 7x + 7

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3 years ago

(2×-5) for ×=-3 and for ×=3.

Brut [27]

Answer:

Step-by-step explanation:

Put the values of x to the given expression:

for x = -3:

2(-3) - 5 = -6 - 5 = -11

for x = 3

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6 0

3 years ago

Can somebody tell me the answer and maybe tell me how you got it too.

asambeis [7]

To get t on one side, we have to use inverse operations to get rid of the 5.

1. Use inverse operation of multiplication to get rid of 5. Which would be division.

2. Divide both sides by 5.

5t/5 = 7 1/2 / 5

3. Solve.

5t/5 = t and 7 1/2 /5 = 1 1/2

7.5 / 5 = 1.5

Therefore, your answer would be C. divide both sides by 5, and the answer is 1 1/2.

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3 years ago

The line L is a tangent to the curve with equation y= 4x^2 +1 . The line L cuts the y axis at (0,8) and has a positive gradient.

sergeinik [125]

A generic point on the graph of the curve has coordinates

$(x, 4x^2+1)$

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$f(x) = 4x^2+1 \implies f'(x) = 8x$

Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through $(k, 4k^2+1)$ and have slope $8k$

So, we can write its equation using the point-slope formula: a line with slope m passing through $(x_0, y_0)$ has equation

$y-y_0 = m(x-x_0)$

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We can rewrite the equation as follows:

$y-4k^2-1 = 8k(x-k) \iff y = 8kx - 8k^2+4k^2+1 \iff y = 8kx-4k^2+1$

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This equation has no real solution, so the problem looks impossible.

5 0

3 years ago