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Gemiola [76]
3 years ago
11

Divide 3/4)1/2 to give the answer

Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0
The exact form will be 3/2 (if you reduce, how many times will one go into three? three times, two will go into 4 twice so that is one way to get the answer.) Decimal form is 1.5 and the mixed number form will be one and one half (or 1 1/2)
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How to put 5/27 into a <br> percentage
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18.5185%

Step-by-step explanation:

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A certain disease occurs most frequently among older women. Of all age groups, women in their 60s have the highest rate of breas
Law Incorporation [45]

Answer:

The probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

Step-by-step explanation:

Let a set be events that have occurred be denoted as:

S = {A₁, A₂, A₃,..., Aₙ}

The Bayes' theorem states that the conditional probability of an event, say <em>A</em>ₙ given that another event, say <em>X</em> has already occurred is given by:

P(A_{n}|X)=\frac{P(X|A_{n})P(A_{n})}{\sum\limits^{n}_{i=1}{P(X|A_{i})P(A_{i})}}

The disease Breast cancer is being studied among women of age 60s.

Denote the events as follows:

<em>B</em> = a women in their 60s has breast cancer

+ = the mammograms detects the breast cancer

The information provided is:

P(B) = 0.0312\\P(+|B)=0.81\\P(+|B^{c})=0.92

Compute the value of P (B|+) using the Bayes' theorem as follows:

P(B|+)=\frac{P(+|B)P(B)}{P(+|B)P(B)+P(+|B^{c})P(B^{c})}

            =\frac{(0.81\times 0.0312)}{(0.81\times 0.0312)+(0.92\times (1-0.0312)}\\

            =\frac{0.025272}{0.025272+0.891296}

            =0.02757\\\approx0.0276

Thus, the probability that a woman in her 60s has breast cancer given that she gets a positive mammogram is 0.0276.

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3 years ago
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