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Alona [7]
3 years ago
11

Consider randomly selecting a single individual and having that person test drive different vehicles. Define events , , and by S

uppose that , , , , , and . What is the probability that the individual likes both vehicle
Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

P(A_1\ n\ A_2) = 0.40

Step-by-step explanation:

Let:

A_1 \to An Individual likes vehicle 1

A_2 \to An Individual like vehicle 2

P(A_1) = 0.55

P(A_2) = 0.65

P (A_1\ u\ A_2 ) = 0.80

Required

P(A_1\ n\ A_2) --- probability that both vehicles are liked by the individual.

This is calculated as:

P(A_1\ n\ A_2) = P(A_1) + P(A_2) - P(A_1\ u\ A_2)

So, we have:

P(A_1\ n\ A_2) = 0.55 + 0.65 - 0.80

P(A_1\ n\ A_2) = 0.40

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Step-by-step explanation:

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2 years ago
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german

Answer:

She is given $205 and spends $57.

She earns $580 and spends $422.

She is given $38 and earns $42.

She earns $56 and is given $59.

Step-by-step explanation:

You just have to do the math.

4 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
Can someone please help me!
Alexeev081 [22]

Answer:

7)no

Step-by-step explanation:

When you plug in the numbers

3(2)-0=-6

6-0=6

6 does not = -6

5 0
3 years ago
Find the greatest number that will divide 63, 45 and 69 so as to leave the same remainder.
jeka57 [31]

Answer:

6

Step-by-step explanation:

Let n be unknown divisor and a be the same remainder, then

63=q_1\cdot n+a\\ \\45=q_2\cdot n+a\\ \\69=q_3\cdot n+a

Subtract a from all equalities:

63-a=q_1\cdot n\\ \\45-a=q_2\cdot n\\ \\69-a=q_3\cdot n

Subtract them:

63-45=(q_1-q_2)n\Rightarrow 18=(q_1-q_2)n\\ \\69-63=(q_3-q_1)n\Rightarrow 6=(q_3-q_1)n\\ \\69-45=(q_3-q_2)n\Rightarrow 24=(q_3-q_2)n

The greatest number is 6. When you divide numbers 63, 45, 69 by 6, you'll get remainders 3, 3, 3, respectively.

7 0
2 years ago
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