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2 years ago

Using the EXCLUSIVE definition of a trapezoid, select the TRUE statement about trapezoids.

Mathematics

1 answer:

kirill115 [55]2 years ago

8 0

A trapezoid has only one pair of parallel sides (the first one)

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Karo-lina-s [1.5K]

16 inches for the answer

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3 years ago

!!!!!!!please help!!!!!!!!

GuDViN [60]

Answer:

The first one is No. The second one I do not know unfortunately.

Step-by-step explanation:

I am in the middle of this lesson in my math class as well and I know that in order to make a triangle, you need the two smaller sides to add up to become larger than the biggest side. In the case of the first question, the two smaller sides, 6 and 3 equal 9, which is not bigger than the biggest side which is 10. I hope you can find the answer to the second one, but for now, the first one is No.

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2 years ago

Solve for x using the correct order operations

madam [21]

It B
x= -12
hope that helps

3 0

2 years ago

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The expression 35 exponet 2 is equivalent to the product of two perfect squares (each greater than 1). You can find the two

raketka [301]

Answer:

Step-by-step explanation:

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3 years ago

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0

3 years ago

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