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3 years ago

Plz help GEOMTRY Only 3 questions did. The slope of M given the following points

Mathematics

1 answer:

Marat540 [252]3 years ago

4 0

Answer:

18.) 3

19.) -4

20.) 1.25 or 1 1/4

Will you please mark me as Brainliest.

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Reciprocate 1 9/11 plz

s344n2d4d5 [400]

Answer:

11/20

Step-by-step explanation:

$\text{First, multiply 1 times 11, and then add the numerator. We have}\\\\\frac{1\cdot11+9}{11}=\frac{20}{11}\\\\\text{Then, reciprocal is just switching the numerator + denenomanator, so we have } \frac{11}{20}$

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2 years ago

Which equation represents a line which is perpendicular to the line y = 3x – 8?

svetoff [14.1K]

It’s wing and Mac and orange

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3 years ago

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Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

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3 years ago

How do I solve for x and y?

Lesechka [4]

Cancel out the terms from one side first then do it for the other one. 4 example make x and individual by multiply the other side by 9 the evaluate. do the same for y

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3 years ago

This is a linear equations question so pls help me I’m dying of stress thank you! ^^

topjm [15]

Answer:

the answer to this problem is D:(-2,4)(1,1)

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2 years ago

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