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Kobotan [32]
3 years ago
8

Identify an equation in point-slope form for the ine parallel to y = -2/3 x+8 that

Mathematics
1 answer:
zlopas [31]3 years ago
4 0

Answer:

y +5 = -\frac{2}{3}(x - 4)

Step-by-step explanation:

Given

y = -\frac{2}{3}x + 8

Point (4,-5)

Required

Determine the line equation

From the question, we understand that the line is parallel to y = -\frac{2}{3}x + 8

This implies that they have the same slope, m

A linear equation is:

y = mx + b

Where

m = slope

By comparison: y = mx + b and y = -\frac{2}{3}x + 8

m = -\frac{2}{3}

Next, we determine the line equation using:

y - y_1 = m(x - x_1)

Where

(x_1,y_1) = (4,-5) and m = -\frac{2}{3}

y - (-5) = -\frac{2}{3}(x - 4)

y +5 = -\frac{2}{3}(x - 4)

Hence,

<em>Option C is correct</em>

<em />

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Step-by-step explanation:

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3 years ago
I) Coordinates of point P
SSSSS [86.1K]

Given:

Five points P, Q, R, S ,T on a coordinate plane.

To find:

The coordinates of (i) P, (ii) Q, (iii) T, (iv) (Ordinate of T) – (Abscissa of R) and (v) (Abscissa of Q) – (Ordinate of S).

Solution:

From the given graph it is clear that the coordinates of given points are

P = (1,1)

Q = (-3,0)

R = (-2,-3)

S = (2,1)

T = (4,-2)

(i)

Coordinates of point P are (1,1).

Therefore, the correct option is (a).

(ii)

Coordinates of point Q are (-3,0).

Therefore, the correct option is (b).

(iii)

Coordinates of point T are (4,-2).

Therefore, the correct option is (c).

(iv)

Ordinate is y-coordinate and abscissa is x-coordinate.

Ordinate of T = -2

Abscissa of R = -2

(Ordinate of T) – (Abscissa of R) = -2 - (-2)

                                                     = -2 + 2

                                                     = 0

Therefore, the correct option is (c).

(v)

Abscissa of Q = -3

Ordinate of S = 1

(Abscissa of Q) – (Ordinate of S) = -3 - 1

                                                      = -4

Therefore, the correct option is (a).

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