To factor it completely you first look at the first term, if the a term is 1 then your good if it is not you need to divide it by whatever number to make the a term 1, in the first question the a term is just x^2 so it's good. Then,you focus on the b and c term, you have to find multiples of term C that adds up to term b. Going back to problem 1, c is 16 and b is 10. So the two factors would be 8 and 2,because 8×2=16 and 8+2=10. the final step is to put into the proper format,
(x+2) (x+3), which would be considered completely factored.
B.) x < -23/4 would be correct
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure
Like terms have the same unknown
25 ab has a and b
look for terms with both a AND b
answer is C
See that odd number are in a Aritmetic progression with a1 = 1 and r = 2
30th number of sequence is given by:
Now you can calculate the sun by: