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3 years ago

Nalil

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

Ya if it was just 18-6 that would be 12 and 3+2 equals 5

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Please Answer ASAP! (NO EXPLANATION NEEDED!) <3

salantis [7]

volume=l1*l2*l3

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8 0

4 years ago

Read 2 more answers

Find an equation of a line with slope -3/4 and that passes through P(-4,6) in standard, form.

SashulF [63]

Answer:

$y = - \frac{3}{4}x + 3$

Step-by-step explanation:

the standard form of any straight line is:

y = m × x + c

where: y is the y value of the point

x is the x value of the point

m is the gradient/slope

SOLUTION

$y = mx + c \\ 6 = - \frac{3}{4} ( - 4) + c \\ c = 3$

3 0

2 years ago

(08.07 HC)

andreev551 [17]

Answer:

$\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}$

$\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

C) See attachment.

Step-by-step explanation:

Given function:

$f(x)=2x^2-x-10$

To factor a <u>quadratic</u> in the form $ax^2+bx+c$ <em> , </em>find two numbers that multiply to $ac$ and sum to $b$ :

$\implies ac=2 \cdot -10=-20$

$\implies b=-1$

Therefore, the two numbers are -5 and 4.

Rewrite $b$ as the sum of these two numbers:

$\implies f(x)=2x^2-5x+4x-10$

Factor the first two terms and the last two terms separately:

$\implies f(x)=x(2x-5)+2(2x-5)$

Factor out the common term (2x - 5):

$\implies f(x)=(x+2)(2x-5)$

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

$\implies (x+2)(2x-5)=0$

Therefore:

$\implies (x+2)=0 \implies x=-2$

$\implies (2x-5)=0 \implies x=\dfrac{5}{2}$

So the x-intercepts are:

$x=-2, \:\:x=\dfrac{5}{2}$

The x-value of the vertex is:

$\implies x=\dfrac{-b}{2a}$

Therefore, the x-value of the vertex of the given function is:

$\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}$

To find the y-value of the vertex, substitute the found value of x into the function:

$\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}$

Therefore, the vertex of the function is:

$\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)$

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards. This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>. Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0

2 years ago

Lisa claims that when multiplying any number between 0 and 10 by 100, the product is greater than 100. What is a possible number

dlinn [17]

The number is 1. 1 multiplied by 100 gives 100 as answer. Lisa claims that <span>when multiplying any number between 0 and 10 by 100, the product is greater than 100. In this case the answer is equal to 100 not greater than 100.

So this proof shows that Lisa's claim is not correct. </span>

3 0

4 years ago

Draw a shape to show 5/2

IRISSAK [1]

This is a tricky question lol. 5/2 = 2.5 , which is half of 5 ... the picture will illustrate half of 5

6 0

3 years ago