Answer:
Each diagonal element will be 3. Off-diagonal elements will be zero.
Step-by-step explanation:
The one that looks like ...
![\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D)
1. Pint
2. Gallon
Hope this helps.
The correct answers are B and D.
A is false because, even though it's true that 4 points are not necessarily on the same line, it is not required that they are collinear in order for them to be coplanar.
B is true: two points always lie on the same line (and thus also in infinite same planes), but four points are not always coplanar
C is false. As a counterexample pick the four points (0,0, 0), (1, 0, 0), (0, 1, 0), (0, 0, 1).
D is true: two points are always on the same line, three points always lie in a common plane, but 4 points are not necessarily coplanar.
Answer:
3, 6, 9, 12
Step-by-step explanation:
3 × 1 = 3
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
15.38. 7, the number in the hundredths place, is turned into 8 due to the following digit, 5. Since it is equal to the minimum, 5, the previous number is rounded up.
