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e-lub [12.9K]
3 years ago
14

X÷3.7=5? Need help.

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

x = 18.5

Step-by-step explanation:

Multiply 5 and 3.7.

Which equals 18.5.

Check: 18.5 / 3.7 = 5.√

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-2w - 23 = 13w +22 please solve
zhannawk [14.2K]

-2w-23=13w+22 is w = -3

6 0
3 years ago
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8 × 10 + 6 − 2 7 + 5 × 8 − 4
riadik2000 [5.3K]

Answer:

95

Step-by-step explanation:

(8)(10)+6−27+(5)(8)−4

=80+6−27+(5)(8)−4

=86−27+(5)(8)−4

=59+(5)(8)−4

=59+40−4

=99−4

=95

hope this helped :)

6 0
3 years ago
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To solve -8p = 48, which of the following could you do to both sides of the equation? A. add -8 B. subtract -8 C. multiply by -8
masya89 [10]

Answer:

D. divide by -8

Step-by-step explanation:

8 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
viktelen [127]
For this case we have the following equation:
 d = 0.5 + 5t
 We will describe the equation step by step.
 0.5: Initial distance Jillian walked
 5: speed with which Jillian begins to jog
 t: independent variable that indicates the number of hours
 y: dependent variable that indicates the distance traveled in miles
 Answer:
 
The variable variable is time and the dependent variable is distance.
3 0
3 years ago
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