1 a)
6^2*6^3= 6^(2+3)=6^5
1b)
(-2)^2 *(-2)^4 = (-2)^(2+4)= (-2)^6=2^6
1c
The diameter of the new rubber ball, to the nearest foot, must be D = 4.0 ft (in the case of the maximum cost).
<h3>
How to find the diameter of the ball?</h3>
Remember that for a sphere of diameter D, the surface area is:
A = 4*pi*(D/2)^2
In this case, the cost is $0.02 per square foot, and the company wants to expend (at maximum) $1 per ball, so first we need to solve:
$0.02*A = $1
A = $1/$0.02 = 50
So the surface of the ball must be 50 square feet.
Then we solve:
50ft^2 = 4*3.14*(D/2)^2
D = 2*√(50 ft^2/(4*3.14)) = 4.0 ft
If you want to learn more about spheres, you can read:
brainly.com/question/10171109
Solution:
Numerator - 4x + y = 8 + 4 = 12
Denominator - 2y - x = 8 - 2 = 6
Final Answer:
12/6 = 2
Answer:
F
Step-by-step explanation:
The formula for the volume of a square-based pyramid is:
V = a2(h/3), where "V" is equal to volume, "a" is equal to base edge, and "h" is equal to height.
You are given the value of the base edge (a = 6)
If the base edge is equal to (1/2)h, or (1/2)h = 6 then, 2(1/2)h = 2(6). This gives you h = 12.
Now you just plug into your formula:
V = 62(12/3) = 36(4) = 144
pls mark brainliest.
