Answer:
Step-by-step explanation:
x² - 24x + 5 = 0
x² - 24x = -5
Now divide the co efficient of x by 2 and square the quotient and add to both sides
24/2 = 12
12² = 144. Now add 144 to both sides of the equation.
x² - 24x + 144 = 5 + 144
x² - 24x + 144 = 149
x² - 2*12*x + 12² = 149
(x - 12)² = 149
Both sides take square root
x - 12 = ±√149
x = 12 ± √149
34 = 2x +8x + 8(3)
34 = 2x + 8x + 24
34 = 10x + 24
10 = 10x
<em><u>x = 1</u></em>
You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).
Answer:
5 units
Step-by-step explanation:
The radius is the distance from the centre of the circle to a point on the circumference.
Use the distance formula to calculate the radius r
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 3, 2) and (x₂, y₂ ) = (1, 5)
r = 
= 
= 
= 
= 5
