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Bond [772]
3 years ago
13

Find the midpoint of the segment with the given endpoints. (7,10) and (-1,-8)

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0

Answer:

Step-by-step explanation:

Hi guy I just wanted to say have a very good day and I hope you are alright today and I hope this helped out your day alright peace out

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so, taking that into account, then \bf \begin{cases}&#10;f(x)=x^3+x^2-6x\\\\&#10;g(x)=6x&#10;\end{cases}\qquad \displaystyle \int\limits_{-4}^{0}\ &#10;\begin{array}{llll}&#10;[ceiling]&-&[floor]\\&#10;f(x)&&g(x)&#10;\end{array}&#10;\\\\\\&#10;thus&#10;\\\\\\&#10;\displaystyle \int\limits_{-4}^{0}\ [[x^3+x^2-6x]-[6x]]dx\implies &#10;\displaystyle \int\limits_{-4}^{0}\ x^3+x^2-12x&#10;\\\\\\&#10;\left. \cfrac{x^4}{4}+\cfrac{x^3}{3}-6x^2  \right]_{0}^{-4}

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Read 2 more answers
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