All categories

3 years ago

I need help my people :-)

Mathematics

1 answer:

lara [203]3 years ago

4 0

Answer:

13.75$

Step-by-step explanation:

First, take 10% of 12.50$. That will give you 1.25$.

Next, add that to 12.50$ to get your new hourly pay.

You might be interested in

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

3 years ago

Dakota's wading pool has a volume of 8,640 cubic inches. Which could be the dimensions of the wading pool? Mark all that apply.

kondor19780726 [428]

The answers are: A and B

5 0

3 years ago

Find the absolute value. 1 -31=___ -1 121=___ -1 -221=___

Veseljchak [2.6K]

I guess we will never know

5 0

2 years ago

Read 2 more answers

Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such

salantis [7]

The right answer will be c.61 that is your answer

8 0

3 years ago

Read 2 more answers

A parking lot has 916 parking spaces that are shaped like parallelograms. The base of each space is 10 feet, and the height of e

dmitriy555 [2]

The area of a parallelogram is $A=bh$

$A=10(18.5) \\ A=185$

I am assuming you're asking for the entire parking lot, so you would have to multiply the above area by 916

$185(916) = 169,460 ft^{2}$

So the answer is (D)

7 0

3 years ago