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AlekseyPX
3 years ago
5

Consider a population with population proportion p, and a sample from the population with sample proportion pˆ. Which of the fol

lowing describes the purpose of the one-sample z-test?[
Mathematics
1 answer:
Deffense [45]3 years ago
3 0

According to CollegeBoard.org:

<u>Answer</u>: "To estimate the probability of observing a value as extreme as  pˆ  given  p."

<u>Explanation</u>: "The test statistic for a one-sample z-test is the distance, in units of standard deviations, between the statistic and the given parameter. From that distance, probabilities (a p-value) can be calculated and a claim can be assessed."

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Darrel divided 575 by 14 by using partial quotients. What is quotient and explain answer using numbers and words
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It at the top all you had to do was divided bot ways you will get that answers

4 0
3 years ago
If there is an open circle on a number on a number line, is that number included in the inequality
natta225 [31]
The answer is NO open circle is not included in an inequality. The other person answered it incorrectly
8 0
3 years ago
What will be the result of substituting 2 for x in both expressions below?
Thepotemich [5.8K]
It’s the first answer, both expressions equal 5 when substituting 2 for x because the expressions are equivalent.

1/2 of x +4
=1/2(2)=1.
1+4= 5

2+6=8
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8 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE!!!
solmaris [256]

Answer:

C

Step-by-step explanation:

cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13

7 0
2 years ago
For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm
Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0
2 years ago
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