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WARRIOR [948]
3 years ago
8

Clayton is at most 2 meters above sea level. Using C for Clayton, which inequality correctly represents this statement?

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

C ≤ 2

Step-by-step explanation:

Given that :

Clayton is at most 2 meters above sea level ;

Let Clayton = C

Clayton's distance can be represented by the inequality :

2 meters above sea level is positive, +2

At most 2 meters above sea level means, Clayton could be anywhere between + 2 metwrs but not more than 2 meters

Hence, Clayton's distance can be represented by the inequality :

C ≤ 2

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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The balls height (h) [in feet] aft
nirvana33 [79]
The ball is at a height of 14 feet after 1.17 and 0.64 seconds.

This is an example of a quadratic equation. Write out the equation with 14 in the place of the height. Then, set it equal to zero.

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0 = -16t^2 + 29t -12

Now, we can use the quadratic equation to solve.
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5 0
3 years ago
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liberstina [14]

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X=7/2

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Step-by-step explanation:

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3 years ago
A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la
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Answer:

Initial value is \frac{1}{2}.

Step-by-step explanation:

Let us assume that the exponential function is f(x) = a(b)^{x} ...... (1)

Now, the point (0,\frac{1}{2}) will satisfy the above equation.

Now, this point on the graph of the exponential function will be sufficient to find the initial value of the function (1) i.e. a.

Now, putting the value x = 0 and y = \frac{1}{2} in the equation (1) we get, f(x) = a(b)^{x}

⇒ \frac{1}{2} = a(b)^{0} = a

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10 0
3 years ago
Read 2 more answers
Graph the equation 3x+3y=−15 using the intercepts.
tatyana61 [14]

Answer:

To find the intercepts, equate one variable to

0

and solve for the other variable:

y-intercept

Set

x

to

0

and solve for

y

giving:

3

x

−

5

y

=

15

becomes:

(

3

⋅

0

)

−

5

y

=

15

0

−

5

y

=

15

−

5

y

=

15

−

5

y

−

5

=

15

−

5

−

5

y

−

5

=

−

3

y

=

−

3

or

(

0

,

−

3

)

x-intercept

Set

y

to

0

and solve for

x

giving:

3

x

−

5

y

=

15

becomes:

3

x

−

(

5

⋅

0

)

=

15

3

x

−

0

=

15

3

x

=

15

3

x

3

=

15

3

3

x

3

=

5

x

=

5

or

(

5

,

0

)

Next. we can plot the two points on the grid:

graph{((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

Then, draw a line through the two points:

graph{(3x - 5y -15)((x-5)^2+(y)^2-0.125)((x)^2+(y+3)^2-0.125)=0 [-20, 20, -10, 10]}

7 0
3 years ago
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