Hi there!
The general formula of A line in slope-intercept form is the following:
In this formula m represents the slope of the line. Therefore, we can conclude that m = 2/5.
We also know that the line passes through the point (-3, -1) and we can therefore substitute this coordinate into the formula of the line.
x = -3 and y = -1
Multiply first.
And finally add 1 1/5 to both sides of the equation.
We can now switch sides.
Now we've found our value of n, which we can substitute into the formula of our line. Hence, in slope-intercept form, we find the following:
Answer:
B
Step-by-step explanation:
because for the X axis you have 10 spaces, which is enough to fit 1 week per space (you only need 8). For the Y axis the best option is 150 because again you have 10 spaces and is enough to fit your numbers.
Answer:
QPN and TSU
Step-by-step explanation:
They're both exterior angles and they are both alternate to each other.
Answer:
The maximum possible number of miles traveled by an automobile included in the histogram is 40,000 miles.
Step-by-step explanation:
A histogram is a bar graph reprinting the frequency of various categories.
In a histogram the <em>y</em>-axis represents the frequency and the <em>x</em>-axis represents the categories.
Consider the histogram provided for the number of miles driven by a sample of automobiles in New York City.
The <em>y</em>-axis represents the frequency and the <em>x</em>-axis represents the number of miles driven.
The category 10,000 miles has the highest frequency at 30.
And the maximum possible number of miles traveled by an automobile is 40,000 miles.
Thus, the maximum possible number of miles traveled by an automobile included in the histogram is 40,000 miles.
Answer:
The correct options are;
1) ΔBCD is similar to ΔBSR
2) BR/RD = BS/SC
3) (BR)(SC) = (RD)(BS)
Step-by-step explanation:
1) Given that RS is parallel to DC, we have;
∠BDC = ∠BRS (Angles on the same side of transversal)
Similarly;
∠BCD = ∠BSR (Angles on the same side of transversal)
∠CBD = ∠CBD = (Reflexive property)
Therefore;
ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency
2) Whereby ΔBCD ~ ΔBSR, we therefore have;
BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1
1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1
SC/BS = RD/BR
Inverting both sides
BR/RD = BS/SC
3) From BR/RD = BS/SC the above we have by cross multiplication;
BR/RD = BS/SC gives;
BR × SC = RD × BR → (BR)(SC) = (RD)(BR).
